Sample Quiz: Physics Chapter 4
Kinematics in Two Dimensions — Physics for Scientists and Engineers: A Strategic Approach (Randall D. Knight)
10 questions · 23 points · answer key included
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Multiple Choice
- A ball is thrown horizontally from the top of a building at 15 m/s. At the same instant, another ball is dropped from rest from the same height. Ignoring air resistance, which statement is correct? (2 PTS)
- The thrown ball hits the ground first because it has initial horizontal velocity.
- The thrown ball takes longer to fall because its horizontal motion interferes with vertical motion.
- Both balls hit the ground at the same time because horizontal and vertical motions are independent.
- The dropped ball hits the ground first because it has no horizontal velocity to slow its fall.
- A spacecraft accelerates at 75 m/s2 at an angle of 25° north of east. What is the y-component (northward) of the spacecraft's acceleration? (2 PTS)
- 106 m/s2
- 68.0 m/s2
- 75 m/s2
- 31.6 m/s2
- A jeepney in Manila travels east at 20 m/s. A passenger on the jeepney throws a ball forward (eastward) at 5 m/s relative to the jeepney. What is the ball's velocity relative to a stationary observer on the street? (2 PTS)
- 25 m/s east
- 15 m/s east
- 5 m/s east
- Cannot be determined without knowing the ball's mass
- A particle moves counterclockwise around a circle at constant speed. Which statement correctly describes the relationship between velocity and acceleration? (2 PTS)
- Velocity is tangent to the circle; acceleration points toward the center of the circle.
- Velocity and acceleration point in the same direction, both tangent to the circle.
- Acceleration is tangent to the circle; velocity points toward the center.
- Both velocity and acceleration point toward the center of the circle.
- A rotating wheel makes 3 complete counterclockwise revolutions in 3 seconds, then reverses direction and makes 1 complete clockwise revolution in 2 seconds. What is the angular velocity during the first 3 seconds? (2 PTS)
- 3π rad/s
- π rad/s
- 2π rad/s
- 6π rad/s
True or False
- In projectile motion, the horizontal and vertical components of motion are independent of each other. (1 PTS)
- The radian is the SI unit of angle and is defined such that an angle of 1 radian corresponds to an arc length equal to the radius of the circle. (1 PTS)
- Angular velocity and angular acceleration must have the same sign when an object is rotating faster and faster. (1 PTS)
Problem Solving
- ApplyA frog jumps at an angle of 30° above the horizontal with an initial speed of 4.62 m/s. Using the range formula for a projectile that lands at the same elevation from which it was launched, calculate how far the frog jumps. (Use g = 9.80 m/s2.) (5 PTS)
- ApplyA projectile is launched with initial velocity components v0x = 9.8 m/s and v0y = 19.6 m/s. Calculate the vertical component of velocity after 1.0 s of flight. (Use g = 9.80 m/s2.) (5 PTS)
Answer key
Multiple Choice
- 1.C — The horizontal and vertical components of projectile motion are independent; both balls fall the same vertical distance in the same time regardless of horizontal velocity.
- 2.D — The y-component of acceleration is ay = (75 m/s2) sin(25°) = 31.6 m/s2, as shown in the worked example for the spacecraft trajectory.
- 3.A — Using the velocity addition formula (vx)CB = (vx)CA + (vx)AB, the ball's velocity relative to the ground is 5 + 20 = 25 m/s east.
- 4.A — In uniform circular motion, the velocity is always tangent to the circle, while the centripetal acceleration always points toward the center, making them perpendicular.
- 5.C — Three counterclockwise revolutions equal 3 × 2π = 6π rad. The angular velocity is ω = Δθ / Δ t = 6π rad / 3 s = 2π rad/s.
True or False
- 1.True — The horizontal velocity remains constant while vertical motion is governed by gravity independently, as stated in the projectile motion principle.
- 2.True — By definition, θ(radians) = s/r, where s is arc length and r is radius, so 1 rad occurs when s = r.
- 3.True — When rotation is speeding up, ω and α have the same sign; when slowing down, they have opposite signs.
Problem Solving
- 1.Use the range formula: range = (v02 sin(2θ))/g. With v0 = 4.62 m/s and θ = 30°: range = ((4.62)2 sin(2 × 30°))/9.80 = (21.34 sin(60°))/9.80 = (21.34 × 0.866)/9.80 = 1.89 m or approximately 1.9 m. — This solution correctly applies the range formula with the given angle and initial speed to find the horizontal distance traveled.
- 2.Use the vertical velocity equation: vy = v0y - gΔ t = 19.6 - (9.80)(1.0) = 19.6 - 9.8 = 9.8 m/s. — This solution correctly applies the kinematic equation for vertical velocity, accounting for the constant downward acceleration due to gravity.